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Chemistry
The minimum pressure required to compress 600 dm3 of a gas at 1 bar to 150 dm3 at 40°C is
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Q. The minimum pressure required to compress $600 \,dm^{3}$ of a gas at $1$ bar to $150\, dm^{3}$ at $40^{\circ}C$ is
NEET
NEET 2020
Some Basic Concepts of Chemistry
A
$4.0$ bar
20%
B
$0.2$ bar
20%
C
$1.0$ bar
20%
D
$2.5$ bar
40%
Solution:
By Boyle's law
$P_{1}V_{1}=P_{2}V_{2}$
$1$ bar $\times 600dm^{3}=P_{2}\times 150\,dm^{3}$
$P_{2}=4$ bar