The minimum energy that must be given to a H atom in ground state so that it can emit an Hγ line in Balmer series is

Question

The minimum energy that must be given to a H atom in ground state so that it can emit an H&gamma; line in Balmer series is (A) 12.4 eV (B) 10.2 eV (C) 13.06 eV (D) 13.6 eV

Tardigrade Admin · Accepted Answer

H&gamma; line in Balmer series corresponds to transition from n = 5 to n = 2 states. Hence, the energy required for this purpose E = E5 - E1 = - (13.6/52) - (-(13.6/12)) = -0.54 + 13. 6 = 13.06 eV

Q. The minimum energy that must be given to a $H$ atom in ground state so that it can emit an $H_{γ}$ line in Balmer series is

$12.4 e V$

$10.2 e V$

$13.06 e V$

$13.6 e V$

$H_{γ}$ line in Balmer series corresponds to transition from $n = 5$ to $n = 2$ states. Hence, the energy required for this purpose
$E = E_{5} - E_{1}$
$= - \frac{13.6}{5 ^{2}} - (- \frac{13.6}{1 ^{2}})$
$= - 0.54 + 13.6$
$= 13.06 e V$

Q. The minimum energy that must be given to a H atom in ground state so that it can emit an Hγ​ line in Balmer series is

12.4eV

10.2eV

13.06eV

13.6eV