Q.
The minimum energy required for the emission of photoelectron from the surface of a metal is 4.95×10−19J . Calculate the critical frequency of the photon required to eject the electron. h=6.6×10−34Jsec .
Minimum energy required for the emission of photoelectrons =4.95×10−19J
Let the critical frequency or threshold frequency of the photon to eject the electron is vsec−1 .
We know, E=hυorυ=hE=6.6×10−344.95×10−19=7.5×1014s−1