The metallic sodium dissolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of :

Question

The metallic sodium dissolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of : (A) solvated electron, e-(NH3)x- (B) solvated atomic sodium, Na(NH3)y (C)  (Na+ + Na-) (D) NaNH2 + H2

Tardigrade Admin · Accepted Answer

All alkali metals dissolve in liquid ammonia

M + (x + y) N H_{3} \to M^{+} (N H_{3})_{x} + e^{-} (N H_{3})_{y}

These electrons are excited to higher energy levels and the absorption of photons occurs in the red region of the spectrum. Thus solution appears blue.

Q. The metallic sodium dissolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of :

solvated electron, $e^{-} (N H_{3})_{x}^{-}$

solvated atomic sodium, $N a (N H_{3})_{y}$

$(N a^{+} + N a^{-})$

$N a N H_{2} + H_{2}$

All alkali metals dissolve in liquid ammonia

$M + (x + y) N H_{3} \to M^{+} (N H_{3})_{x} + e^{-} (N H_{3})_{y}$

These electrons are excited to higher energy levels and the absorption of photons occurs in the red region of the spectrum. Thus solution appears blue.

Q. The metallic sodium dissolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of :

solvated electron, e−(NH3​)x−​

solvated atomic sodium, Na(NH3​)y​

(Na++Na−)

NaNH2​+H2​

All alkali metals dissolve in liquid ammonia M+(x+y)NH3​→M+(NH3​)x​+e−(NH3​)y​ These electrons are excited to higher energy levels and the absorption of photons occurs in the red region of the spectrum. Thus solution appears blue.

solvated electron, $e^{-} (N H_{3})_{x}^{-}$

solvated atomic sodium, $N a (N H_{3})_{y}$

$(N a^{+} + N a^{-})$

$N a N H_{2} + H_{2}$

All alkali metals dissolve in liquid ammonia

$M + (x + y) N H_{3} \to M^{+} (N H_{3})_{x} + e^{-} (N H_{3})_{y}$

These electrons are excited to higher energy levels and the absorption of photons occurs in the red region of the spectrum. Thus solution appears blue.