Question

The melting point of $SnC{l}_4$ is less than $SnC{l}_2$ because in comparison of $S{n}^{2+}$

• A. the size of $S{n}^{4+}$ is smaller
• B. more positive charge on $S{n}^{4+}$
• C. the ionization potential of $S{n}^{4+}$ is more
• D. the structure of $SnC{l}_4$ is tetrahedral

Answer 1

Answer: (C)

The melting point of $SnC{l}_4$ is less than $SnC{l}_2$ because the ionization potential of $S{n}^{4+}$ is more than $S{n}^{2+}$ .