The mean weight of 9 items is 15 . If one more item is added to the series, the mean becomes 16 Then find value of 10 text th item.

Question

The mean weight of 9 items is 15 . If one more item is added to the series, the mean becomes 16 Then find value of 10 text th item. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

( Sigma x i /9)=15 ⇒ Sigma x i =135 ( Sigma x i '/10)=16 ⇒ Sigma x i '=160 10 text th date = Sigma x i '- Sigma x i =160-135=25

Q. The mean weight of $9$ items is $15$ . If one more item is added to the series, the mean becomes $16$ Then find value of $1 0^{th}$ item.

$\frac{Σ x _{i}}{9} = 15$
$\Rightarrow Σ x_{i} = 135$
$\frac{Σ x _{i} ^{'}}{10} = 16$
$\Rightarrow Σ x_{i}^{'} = 160$
$1 0^{th}$ date $= Σ x_{i}^{'} - Σ x_{i}$
$= 160 - 135 = 25$

Q. The mean weight of 9 items is 15 . If one more item is added to the series, the mean becomes 16 Then find value of 10th item.

9Σxi​​=15 ⇒Σxi​=135 10Σxi​′​=16 ⇒Σxi​′=160 10th date =Σxi​′−Σxi​ =160−135=25

Q. The mean weight of $9$ items is $15$ . If one more item is added to the series, the mean becomes $16$ Then find value of $1 0^{th}$ item.

$\frac{Σ x _{i}}{9} = 15$
$\Rightarrow Σ x_{i} = 135$
$\frac{Σ x _{i} ^{'}}{10} = 16$
$\Rightarrow Σ x_{i}^{'} = 160$
$1 0^{th}$ date $= Σ x_{i}^{'} - Σ x_{i}$
$= 160 - 135 = 25$