The mean time period of second's pendulum is 2.00 s and mean absolute error in the time period is 0.05 s . To express maximum estimate of error, the time period should be written as

Question

The mean time period of second's pendulum is 2.00 s and mean absolute error in the time period is 0.05 s . To express maximum estimate of error, the time period should be written as (A) (2.00 ± 0.01) s (B) (2.00 ± 0.025) s  (C) (2 .00 ± 0 .05) s  (D) (2.00 ± 0.10) s

Tardigrade Admin · Accepted Answer

Mean time period T=2.00 s and Mean absolute error =Δ T=0.05 s To express maximum estimate of error, the time period should be written as (2.0 ± 0.05) s

Q. The mean time period of second's pendulum is $2.00 s$ and mean absolute error in the time period is $0.05 s$ . To express maximum estimate of error, the time period should be written as

$(2.00 \pm 0.01) s$

$(2.00 \pm 0.025) s$

$(2.00 \pm 0.05) s$

$(2.00 \pm 0.10) s$

Mean time period $T = 2.00 s$ and Mean absolute error $= Δ T = 0.05 s$
To express maximum estimate of error, the time period should be written as $(2.0 \pm 0.05) s$

Q. The mean time period of second's pendulum is 2.00s and mean absolute error in the time period is 0.05s . To express maximum estimate of error, the time period should be written as

(2.00±0.01)s

(2.00±0.025)s

(2.00±0.05)s

(2.00±0.10)s