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Q. The mean time period of second's pendulum is $2.00 \, s$ and mean absolute error in the time period is $0.05 \, s$ . To express maximum estimate of error, the time period should be written as

NTA AbhyasNTA Abhyas 2022

Solution:

Mean time period $T=2.00 \, s$ and Mean absolute error $=\Delta T=0.05 \, s$
To express maximum estimate of error, the time period should be written as $\left(2.0 \pm 0.05\right) \, s$