The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is

Question

The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is (A) 48 (B) 36 (C) 38 (D) none of these

Tardigrade Admin · Accepted Answer

The sum of all the 50 observations = 36 × 50 = 1800. Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 × 36. So, the mean of remaining 48 observations is 36.

Q. The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is

48

36

38

none of these

The sum of all the 50 observations = 36 $\times$ 50 = 1800.
Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 $\times$ 36.
So, the mean of remaining 48 observations is 36.