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  4. The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is

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Q. The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is

Statistics

Solution:

The sum of all the 50 observations = 36 $\times$ 50 = 1800.
Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 $\times$ 36.
So, the mean of remaining 48 observations is 36.