The mean of 50 observations is 36 . If its two observations 30 and 42 are deleted, then the mean of the remaining observations is-

Question

The mean of 50 observations is 36 . If its two observations 30 and 42 are deleted, then the mean of the remaining observations is- (A) 48 (B) 36 (C) 38 (D) none of these

Tardigrade Admin · Accepted Answer

∵ Sum of the 50 observations =3650=1800 Two observations 30 and 42 are deleted Sum of the remaining 48 observations =1800-[30+42]=1728 Req. mean =(1728/48)=36

Q. The mean of $50$ observations is $36$ . If its two observations $30$ and $42$ are deleted, then the mean of the remaining observations is-

48

36

38

none of these

$∵$ Sum of the $50$ observations $= 3650 = 1800$
Two observations $30$ and $42$ are deleted
Sum of the remaining $48$ observations
$= 1800 - [30 + 42] = 1728$
Req. mean $= \frac{1728}{48} = 36$

Q. The mean of 50 observations is 36 . If its two observations 30 and 42 are deleted, then the mean of the remaining observations is-

48

36

38

none of these

∵ Sum of the 50 observations =3650=1800 Two observations 30 and 42 are deleted Sum of the remaining 48 observations =1800−[30+42]=1728 Req. mean =481728​=36

Q. The mean of $50$ observations is $36$ . If its two observations $30$ and $42$ are deleted, then the mean of the remaining observations is-

$∵$ Sum of the $50$ observations $= 3650 = 1800$
Two observations $30$ and $42$ are deleted
Sum of the remaining $48$ observations
$= 1800 - [30 + 42] = 1728$
Req. mean $= \frac{1728}{48} = 36$