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  4. The mean of 50 observations is 36 . If its two observations 30 and 42 are deleted, then the mean of the remaining observations is-

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Q. The mean of $50$ observations is $36$ . If its two observations $30$ and $42$ are deleted, then the mean of the remaining observations is-

Statistics

Solution:

$\because$ Sum of the $50$ observations $=3650=1800$
Two observations $30$ and $42$ are deleted
Sum of the remaining $48$ observations
$=1800-[30+42]=1728$
Req. mean $=\frac{1728}{48}=36$