Q.
The mean and the variance of five observation are 4 and 5.20, respectively. If three of the observations are 3,4 and 4; then then absolute value of the difference of the other two observations, is :
meanxˉ=4,σ2=5.2,n=5,.x1=3,x2=4=x3 ∑xi=20 x4+x5=9.....(i) x∑xi2−(xˉ)2σ2⇒∑xi2=106 x42+x52=65......(ii)
Using (i) and (ii) (x4−x5)2=49 ∣x4−x5∣=7