The mean and the median of the following ten numbers in increasing order 10, 22, 26, 29, 34, x 42, 67, 70, y are 42 and 35 respectively, then (y/x) is equal to :

Question

The mean and the median of the following ten numbers in increasing order 10, 22, 26, 29, 34, x 42, 67, 70, y are 42 and 35 respectively, then (y/x) is equal to : (A) 7/3 (B) 9/4 (C) 7/2 (D) 8/3

Tardigrade Admin · Accepted Answer

(34+x/2) =35 x=36 42 = (10+22+26+29+34+36+42+67+70+y/10) 420-336 =y ⇒ y = 84 (y/x) = (84/36) = (7/3)

Q. The mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x 42, 67, 70, y$ are $42$ and $35$ respectively, then $\frac{y}{x}$ is equal to :

7/3

9/4

7/2

8/3

$\frac{34 + x}{2} = 35$
$x = 36$
$42 = \frac{10 + 22 + 26 + 29 + 34 + 36 + 42 + 67 + 70 + y}{10}$
$420 - 336 = y \Rightarrow y = 84$
$\frac{y}{x} = \frac{84}{36} = \frac{7}{3}$

Q. The mean and the median of the following ten numbers in increasing order 10,22,26,29,34,x42,67,70,y are 42 and 35 respectively, then xy​ is equal to :

7/3

9/4

7/2

8/3

234+x​=35 x=36 42=1010+22+26+29+34+36+42+67+70+y​ 420−336=y⇒y=84 xy​=3684​=37​

Q. The mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x 42, 67, 70, y$ are $42$ and $35$ respectively, then $\frac{y}{x}$ is equal to :

$\frac{34 + x}{2} = 35$
$x = 36$
$42 = \frac{10 + 22 + 26 + 29 + 34 + 36 + 42 + 67 + 70 + y}{10}$
$420 - 336 = y \Rightarrow y = 84$
$\frac{y}{x} = \frac{84}{36} = \frac{7}{3}$