The maximum wavelength of radiation emitted at 900 K is 4 μ m. The maximum wavelength of radiation emitted at 1200 K, will be :

Question

The maximum wavelength of radiation emitted at 900 K is 4 μ m. The maximum wavelength of radiation emitted at 1200 K, will be : (A) 1 m (B) 1 μ m (C) 0.3 μ m (D) 3 μ m

Tardigrade Admin · Accepted Answer

From Wien's displacement law λm T= constant where λm is the maximum wavelength emitted and T is absolute temperature. λ1 T1 =λ2 T2 ⇒ 4 × 900 =1200 × λ2 ⇒ λ2 =(4 × 900/1200)=3 μ m

Q. The maximum wavelength of radiation emitted at $900 K$ is $4 μ m$ . The maximum wavelength of radiation emitted at $1200 K$ , will be :

1 m

$1 μ m$

$0.3 μ m$

$3 μ m$

From Wien's displacement law
$λ_{m} T =$ constant
where $λ_{m}$ is the maximum wavelength emitted and $T$ is absolute temperature.
$λ_{1} T_{1} = λ_{2} T_{2}$
$\Rightarrow 4 \times 900 = 1200 \times λ_{2}$
$\Rightarrow λ_{2} = \frac{4 \times 900}{1200} = 3 μ m$

Q. The maximum wavelength of radiation emitted at 900K is 4μm. The maximum wavelength of radiation emitted at 1200K, will be :

1 m

1μm

0.3μm

3μm

From Wien's displacement law λm​T= constant where λm​ is the maximum wavelength emitted and T is absolute temperature. λ1​T1​=λ2​T2​ ⇒4×900=1200×λ2​ ⇒λ2​=12004×900​=3μm

Q. The maximum wavelength of radiation emitted at $900 K$ is $4 μ m$ . The maximum wavelength of radiation emitted at $1200 K$ , will be :

$1 μ m$

$0.3 μ m$

$3 μ m$

From Wien's displacement law
$λ_{m} T =$ constant
where $λ_{m}$ is the maximum wavelength emitted and $T$ is absolute temperature.
$λ_{1} T_{1} = λ_{2} T_{2}$
$\Rightarrow 4 \times 900 = 1200 \times λ_{2}$
$\Rightarrow λ_{2} = \frac{4 \times 900}{1200} = 3 μ m$