Question

The maximum wavelength of Brackett series of hydrogen atom will be______$A^{\circ }$

• A. 35,890
• B. 14,440
• C. 62,160
• D. 40,400

Answer 1

Answer: (D)

$R{Z}^2\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)=\frac{1}{\lambda }$
$Where{n}_1$ = 4 ; $n_2$ = 5