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  4. The maximum wavelength of Brackett series of hydrogen atom will beA°

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Q. The maximum wavelength of Brackett series of hydrogen atom will be______$A^\circ$

Atoms

Solution:

$RZ^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) = \frac{1}{\lambda}$
$Where \, n_1$ = 4 ; $n_2$ = 5