The maximum velocity of an electron emitted by light of wavelength λ incident on the surface of a metal of work function φ is :

Question

The maximum velocity of an electron emitted by light of wavelength λ incident on the surface of a metal of work function φ is : (A) [(2( hc +λ φ)/ m λ)]1 / 2 (B) [(2( hc -λ φ)/ m λ)]1 / 2 (C) (2( hc -λ φ)/ m ) (D) [(2( h λ-φ)/ m )]1 / 2

Tardigrade Admin · Accepted Answer

( hc /λ)-φ=(1/2) mv 2 √2(( hc -λ φ/λ m ))= V

Q. The maximum velocity of an electron emitted by light of wavelength $λ$ incident on the surface of a metal of work function $ϕ$ is :

$[\frac{2 ( h c + λ ϕ )}{mλ}]^{1/2}$

$[\frac{2 ( h c - λ ϕ )}{mλ}]^{1/2}$

$\frac{2 ( h c - λ ϕ )}{m}$

$[\frac{2 ( hλ - ϕ )}{m}]^{1/2}$

$\frac{h c}{λ} - ϕ = \frac{1}{2} m v^{2}$
$2 (\frac{h c - λ ϕ}{λm}) = V$

Q. The maximum velocity of an electron emitted by light of wavelength λ incident on the surface of a metal of work function ϕ is :

[mλ2(hc+λϕ)​]1/2

[mλ2(hc−λϕ)​]1/2

m2(hc−λϕ)​

[m2(hλ−ϕ)​]1/2