Given : x+2y≥2...(1) x+2y≤8...(2)
and x,y≥0
For equation (1) 2x+1y=1 and for equation ( 2 ) 8x+4y=1
Given : z=3x+2y
At point (2,0);z=3×2+0=6
At point (0,1);z=3×0+2×1=2
At point (8,0);z=3×8+2×0=24
At point (0,4);z=3×0+2×4=8 ∴ maximum value of z is 24 at point (8,0)