Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The maximum value of P = x + 3y such that 2x + y ≤ 20 , x + 2y ≤ 20 , x ≥ 0 , y ≥ 0 , is
Q. The maximum value of
P
=
x
+
3
y
such that
2
x
+
y
≤
20
,
x
+
2
y
≤
20
,
x
≥
0
,
y
≥
0
,
is
4915
181
Linear Programming
Report Error
A
10
12%
B
60
30%
C
30
42%
D
None of these
16%
Solution:
Obviously,
P
=
x
+
3
y
will be maximum at (0, 10).
∴
P
=
0
+
3
×
10
=
30.