Question

The maximum value of $\mu =3x+4y,$ subject to the condition $x+y\le 40,x+2y\le 60,x,y\ge 0$ is

• A. 160
• B. 120
• C. 100
• D. 140

Answer 1

Answer: (D)

Given, $P=3x+4y$
This graph has been draw from given constraints and maximum value of P will be at A or B or C .
$P_A=P_{(0,30)}=3\times 0+4\times 30=120$
$P_B=P_{(20,20)}=3\times 20+4\times 20=140$
$P_C=P_{(40,0)}=3\times 40+0=120$
Therefore $P_{max}=140$