The maximum range of a projectile fired with some initial velocity is found to be 1000 metre, in the absence of wind and air resistance. The maximum height h reached by this projectile is

Question

The maximum range of a projectile fired with some initial velocity is found to be 1000 metre, in the absence of wind and air resistance. The maximum height h reached by this projectile is (A) 250 m (B) 500 m (C) 1000 m (D) 2000 m

Tardigrade Admin · Accepted Answer

Rmax = (u2/g) = 1000 m (R is maximum when θ = 45Â°) H = (u2 sin2 θ/2g) = (u2/2g) × sin2 45° = (1000/4) = 250 m

Q. The maximum range of a projectile fired with some initial velocity is found to be 1000 metre, in the absence of wind and air resistance. The maximum height h reached by this projectile is

250 m

500 m

1000 m

2000 m

$R_{ma x} = \frac{u ^{2}}{g} = 1000 m$
(R is maximum when $θ$ = 45°)
$H = \frac{u ^{2} s i n ^{2} θ}{2 g} = \frac{u ^{2}}{2 g} \times sin^{2} 4 5^{\circ}$
$= \frac{1000}{4} = 250 m$

Q. The maximum range of a projectile fired with some initial velocity is found to be 1000 metre, in the absence of wind and air resistance. The maximum height h reached by this projectile is

250 m

500 m

1000 m

2000 m

Rmax​=gu2​=1000m (R is maximum when θ = 45°) H=2gu2sin2θ​=2gu2​×sin245∘ =41000​=250m

$R_{ma x} = \frac{u ^{2}}{g} = 1000 m$
(R is maximum when $θ$ = 45°)
$H = \frac{u ^{2} s i n ^{2} θ}{2 g} = \frac{u ^{2}}{2 g} \times sin^{2} 4 5^{\circ}$
$= \frac{1000}{4} = 250 m$