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Tardigrade
Question
Chemistry
The maximum number of 3 d electrons having s =+1 / 2 are
Q. The maximum number of
3
d
electrons having
s
=
+
1/2
are
1703
229
Structure of Atom
Report Error
A
10
B
5
C
14
D
7
Solution:
3
d
=
Max
10
e
−
5
e
−
5
e
−