The maximum kinetic energy of photoelectrons coming out of a metal surface is 10 eV. The minimum voltage required to stop, the emission of electrons from this metal surface is

Question

The maximum kinetic energy of photoelectrons coming out of a metal surface is 10 eV. The minimum voltage required to stop, the emission of electrons from this metal surface is (A) 10 V (B) 5 V (C) -5 V (D) -10 V

Tardigrade Admin · Accepted Answer

The minimum negative potential V0 is called stopping potential. Here, K max =10 eV So, the stopping potential, e V0=K max ⇒ eV 0=10 eV Or V0=-10 V

Q. The maximum kinetic energy of photoelectrons coming out of a metal surface is $10 e V$ . The minimum voltage required to stop, the emission of electrons from this metal surface is

10 V

5 V

-5 V

-10 V

The minimum negative potential $V_{0}$ is called stopping potential.
Here, $K_{m a x} = 10 e V$
So, the stopping potential, $e V_{0} = K_{m a x}$
$\Rightarrow e V_{0} = 10 e V$
Or $V_{0} = - 10 V$

Q. The maximum kinetic energy of photoelectrons coming out of a metal surface is 10eV. The minimum voltage required to stop, the emission of electrons from this metal surface is

10 V

5 V

-5 V

-10 V

The minimum negative potential V0​ is called stopping potential. Here, Kmax​=10eV So, the stopping potential, eV0​=Kmax​ ⇒eV0​=10eV Or V0​=−10V

Q. The maximum kinetic energy of photoelectrons coming out of a metal surface is $10 e V$ . The minimum voltage required to stop, the emission of electrons from this metal surface is

The minimum negative potential $V_{0}$ is called stopping potential.
Here, $K_{m a x} = 10 e V$
So, the stopping potential, $e V_{0} = K_{m a x}$
$\Rightarrow e V_{0} = 10 e V$
Or $V_{0} = - 10 V$