The maximum kinetic energy of emitted photoelectrons depends on

Question

The maximum kinetic energy of emitted photoelectrons depends on (A) Intensity of incident radiation (B) Frequency of incdent radiation (C) Speed of incident radiation (D) Number of photons in the incident radiation

Tardigrade Admin · Accepted Answer

K E = (1/2) m vmax2 = h (. ν - (ν)o .) K . Emax = h ν - h νo ∴ KEm a x depends on frequency of incident radiation

Q. The maximum kinetic energy of emitted photoelectrons depends on

Intensity of incident radiation

Frequency of incdent radiation

Speed of incident radiation

Number of photons in the incident radiation

$K E = \frac{1}{2} m v_{ma x}^{2} = h (ν - (ν)_{o})$
$K . E_{ma x} = h ν - h ν_{o}$
$∴ K E_{ma x}$ depends on frequency of incident radiation

Q. The maximum kinetic energy of emitted photoelectrons depends on

Intensity of incident radiation

Frequency of incdent radiation

Speed of incident radiation

Number of photons in the incident radiation

KE=21​mvmax2​=h(ν−(ν)o​) K.Emax​=hν−hνo​ ∴KEmax​ depends on frequency of incident radiation

$K E = \frac{1}{2} m v_{ma x}^{2} = h (ν - (ν)_{o})$
$K . E_{ma x} = h ν - h ν_{o}$
$∴ K E_{ma x}$ depends on frequency of incident radiation