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  4. The maximum kinetic energy of emitted photoelectrons depends on

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Q. The maximum kinetic energy of emitted photoelectrons depends on

NTA AbhyasNTA Abhyas 2022

Solution:

$K E = \frac{1}{2} m v_{max}^{2} = h \left(\right. \nu - \left(\nu\right)_{o} \left.\right)$
$K . E_{max} = h \nu - h \nu_{o}$
$\therefore \, KE_{m a x}$ depends on frequency of incident radiation