The maximum intensity of fringes in Youngs experiment is I. If one of the slit is closed then the intensity at that place becomes I0 . Which of the following relation is true?

Question

The maximum intensity of fringes in Youngs experiment is I. If one of the slit is closed then the intensity at that place becomes I0 . Which of the following relation is true? (A) I=I0 (B) I=2I0 (C) I=4I0 (D) There is no relation between I and I0

Tardigrade Admin · Accepted Answer

Suppose slit width's are equal so they produces waves of equal intensity say I'. Resultant intensity at any point

I_{R} = 4 I^{'} cos^{2} ϕ

where

ϕ

is the phase difference between the waves at the point of observation.
For maximum intensity,

ϕ = 0^{\circ}

\Rightarrow I_{m a x} = 4 I^{'} = I

...(i)
If one of slit is closed, resultant intensity at the same point will be

I^{'}

only
ie,

I^{'} = I_{0}

...(ii)
Comparing Eqs. (i) and (ii) we get

I = 4 I_{0}

Q. The maximum intensity of fringes in Youngs experiment is $I$ . If one of the slit is closed then the intensity at that place becomes $I_{0}$ . Which of the following relation is true?

$I = I_{0}$

$I = 2 I_{0}$

$I = 4 I_{0}$

There is no relation between $I$ and $I_{0}$

Q. The maximum intensity of fringes in Youngs experiment is I. If one of the slit is closed then the intensity at that place becomes I0​ . Which of the following relation is true?

I=I0​

I=2I0​

I=4I0​

There is no relation between I and I0​

Q. The maximum intensity of fringes in Youngs experiment is $I$ . If one of the slit is closed then the intensity at that place becomes $I_{0}$ . Which of the following relation is true?

$I = I_{0}$

$I = 2 I_{0}$

$I = 4 I_{0}$

There is no relation between $I$ and $I_{0}$