Question

The mass of ship is $2\times 10^{7}kg$. On applying a fore of $25\times 10^{5}N$, it is displaced through $25m$. After the displacement. The speed aquired by the ship will be :

• A. 12.5 m/s
• B. 5 m/s
• C. 3.7 m/s
• D. 2.5 m/s

Answer 1

Answer: (D)

Here : Mass of ship $m=2\times 10^{7}kg$
Force $F=25\times 10^{5}N$
Displacement $s=25m$
According to the Newton's second law of motion
$F=ma$
or $a=\frac{F}{m}=\frac{25\times 10^5}{2\times 10^7}$
$=12.5\times 10^{-2}m/s^2$
The relation for final velocity is
$v^2=u^2+2as$
or $v^2=0+2\times \left(12.5\times 10^{-2}\right)\times 25$
or $v=\sqrt{6.25}=2.5m/s$