The mass of potassium dichromate crystals required to oxidise 750 cm3 of 0.6 M Mohr's salt solution is: (Given molar mass potassium dichromate = 294, Mohr's salt = 392)

Question

The mass of potassium dichromate crystals required to oxidise 750 cm3 of 0.6 M Mohr's salt solution is: (Given molar mass potassium dichromate = 294, Mohr's salt = 392) (A) 0.45 g (B) 22.05 g (C) 2.2 g (D) 0.49 g

Tardigrade Admin · Accepted Answer

0.6×0.75×1 = (w/294)×6 w = 22.05 g

Q. The mass of potassium dichromate crystals required to oxidise $750 c m^{3}$ of 0.6 M Mohr's salt solution is :
(Given molar mass potassium dichromate = 294, Mohr's salt = 392)

0.45 g

22.05 g

2.2 g

0.49 g

$0.6 \times 0.75 \times 1 = \frac{w}{294} \times 6$
$w = 22.05 g$

Q. The mass of potassium dichromate crystals required to oxidise 750cm3 of 0.6 M Mohr's salt solution is : (Given molar mass potassium dichromate = 294, Mohr's salt = 392)