The mass of Mg 3 N 2 produced if 48 g of Mg metal is reacted with 34 g NH 3 gas is: 3 Mg +2 NH 3 longrightarrow Mg 3 N 2+3 H 2

Question

The mass of Mg 3 N 2 produced if 48 g of Mg metal is reacted with 34 g NH 3 gas is: 3 Mg +2 NH 3 longrightarrow Mg 3 N 2+3 H 2 (A) (200/3) (B) (100/3) (C) (400/3) (D) (150/3)

Tardigrade Admin · Accepted Answer

3 Mg +2 NH 3 arrow Mg 3 N 2+3 H 2 Mole (48/24)=2 (34/17)=2 ∴ Mass of (1/3) × 2 ×(3 × 24+28)=(200/3)

Q. The mass of $M g_{3} N_{2}$ produced if $48 g$ of $M g$ metal is reacted with $34 g N H_{3}$ gas is:
$3 M g + 2 N H_{3} ⟶ M g_{3} N_{2} + 3 H_{2}$

$\frac{200}{3}$

$\frac{100}{3}$

$\frac{400}{3}$

$\frac{150}{3}$

$3 M g + 2 N H_{3} \to M g_{3} N_{2} + 3 H_{2}$

Mole $\frac{48}{24} = 2 \frac{34}{17} = 2$

$∴$ Mass of $\frac{1}{3} \times 2 \times (3 \times 24 + 28) = \frac{200}{3}$

Q. The mass of Mg3​N2​ produced if 48g of Mg metal is reacted with 34gNH3​ gas is: 3Mg+2NH3​⟶Mg3​N2​+3H2​

3200​

3100​

3400​

3150​