Question

The mass of $Mg _{3} N _{2}$ produced if $48\, g$ of $Mg$ metal is reacted with $34 \,g \,NH _{3}$ gas is:
$3 \,Mg +2 \,NH _{3} \longrightarrow Mg _{3} N _{2}+3 H _{2}$

• A. $\frac{200}{3}$
• B. $\frac{100}{3}$
• C. $\frac{400}{3}$
• D. $\frac{150}{3}$

Answer 1

Answer: (A)

$3 \,Mg +2 NH _{3} \rightarrow Mg _{3} N _{2}+3 H _{2}$

Mole $\frac{48}{24}=2 \frac{34}{17}=2$

$\therefore $ Mass of $\frac{1}{3} \times 2 \times(3 \times 24+28)=\frac{200}{3}$