The mass of gas adsorbed, x, per unit mass of adsorbate, m , was measured at various pressures, p. A graph between log ( x / m ) and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771 . The value of (x/m) at a pressure of 4 atm is: (Given log 3=0.4771 )

Question

The mass of gas adsorbed, x, per unit mass of adsorbate, m , was measured at various pressures, p. A graph between log ( x / m ) and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771 . The value of (x/m) at a pressure of 4 atm is: (Given log 3=0.4771 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(x/m)=k px ldots(1) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7de29904c401e180c1f78fbf2b0a12f2-.png" /> Given c= log k=0.4771 or k=3 slope x=2 put in eq. (1) (x/m)=3 ×(4)2 ⇒ 48

Q. The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between logmx​ and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of mx​ at a pressure of 4 atm is : (Given log3=0.4771 )

mx​=kpx…(1) Given c=logk=0.4771 or k=3 slope x=2 put in eq. (1) mx​=3×(4)2 ⇒48

$\frac{x}{m} = k p^{x} \dots (1)$

Given $c = lo g k = 0.4771$ or $k = 3$

slope $x = 2$

put in eq. (1) $\frac{x}{m} = 3 \times (4)^{2}$

$\Rightarrow 48$