Question

The mass of a simple pendulum bob is $100gm$. The length of the pendulum is $1m$ The bob is drawn aside from the equilibrium position so that the string makes an angle of $60^{\circ }$ with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

• A. $0.49J$
• B. $0.94J$
• C. $1J$
• D. $1.2J$

Answer 1

Answer: (A)

$KE=mgl[1-\cos \theta ]$