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Punjab PMETPunjab PMET 2006Structure of Atom
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Solution:
We know that E=mc2=λhc ∴λ=mch
or m=λch
Where, λ= wavelength of photon h= planck's constant m= mass of photon c= velocity of light
Given, λ=3.6A˚=3.6×10−10m ∴m=3.6×10−10×3×1086.62×10−34 =6.135×10−33kg