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Question
Chemistry
The mass of 70% H2SO4 by mass required for neutralisation of 1 mol of NaOH is
Q. The mass of 70%
H
2
S
O
4
by mass required for neutralisation of 1 mol of NaOH is
3467
224
Some Basic Concepts of Chemistry
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A
49 g
6%
B
98 g
7%
C
70 g
75%
D
34.3 g
12%
Solution:
2
N
a
O
H
+
H
2
S
O
4
→
N
a
2
S
O
4
+
H
2
O
Pure
H
2
S
O
4
required for
1
mole of
N
a
O
H
=
2
1
mol
=
49
g
70%
H
2
S
O
4
required for
1
mole of
N
a
O
H
=
70
49
×
100
=
70
g