The major product obtained when Br2/Fe is treated with

Question

The major product obtained when Br2/Fe is treated with (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6b90fb87a579a76032ec0fd82efb874a-.jpeg" /> Electrophilic substitution takes place at electron rich positions. The ring attached with - NH will have rich electron density due to resonance. As ortho-position is blocked, the electrophile attacks the para-position.

Q. The major product obtained when $B r_{2} / F e$ is treated with

Electrophilic substitution takes place at electron rich positions. The ring attached with $- N H$ will have rich electron density due to resonance. As ortho-position is blocked, the electrophile attacks the para-position.

Q. The major product obtained when Br2​/Fe is treated with

Electrophilic substitution takes place at electron rich positions. The ring attached with −NH will have rich electron density due to resonance. As ortho-position is blocked, the electrophile attacks the para-position.

Q. The major product obtained when $B r_{2} / F e$ is treated with

Electrophilic substitution takes place at electron rich positions. The ring attached with $- N H$ will have rich electron density due to resonance. As ortho-position is blocked, the electrophile attacks the para-position.