The main scale of a vernier calipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The reading for shown situation is found to be (12 x/10) mm. Find the value of x.

Question

The main scale of a vernier calipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The reading for shown situation is found to be (12 x/10) mm. Find the value of x. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Least count (1 mm /10)=0.1 mm Zero error =-(10-6) × 0.1=-0.4 mm Reading =6+5 ×(0.1)-(-0.4)=7.2 mm ⇒ x=6

Q. The main scale of a vernier calipers reads in millimeter and its vernier is divided into $10$ divisions which coincides with $9$ divisions of the main scale. The reading for shown situation is found to be $\frac{12 x}{10} mm$ . Find the value of $x$ .

Least count $\frac{1 mm}{10} = 0.1 mm$
Zero error $= - (10 - 6) \times 0.1 = - 0.4 mm$
Reading $= 6 + 5 \times (0.1) - (- 0.4) = 7.2 mm$
$\Rightarrow x = 6$

Q. The main scale of a vernier calipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The reading for shown situation is found to be 1012x​mm. Find the value of x.

Least count 101mm​=0.1mm Zero error =−(10−6)×0.1=−0.4mm Reading =6+5×(0.1)−(−0.4)=7.2mm ⇒x=6

Q. The main scale of a vernier calipers reads in millimeter and its vernier is divided into $10$ divisions which coincides with $9$ divisions of the main scale. The reading for shown situation is found to be $\frac{12 x}{10} mm$ . Find the value of $x$ .

Least count $\frac{1 mm}{10} = 0.1 mm$
Zero error $= - (10 - 6) \times 0.1 = - 0.4 mm$
Reading $= 6 + 5 \times (0.1) - (- 0.4) = 7.2 mm$
$\Rightarrow x = 6$