The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12 cm carrying a current of 2 A is

Question

The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12 cm carrying a current of 2 A is (A) 18 G (B) 19.7 G (C) 15.7 G (D) 17.7 G

Tardigrade Admin · Accepted Answer

Here N= 150, R=12 cm =12×10-2 m, I=2 A ∴ B=(μ0 NI/2R) =(2π×10-7×150×2/12×10-2) =1.57×10-3 T =1.57×10-3 T =15.7×10-4 T =15.7 G

Q. The magnitude of the magnetic field at the centre of the tightly wound $150$ turn coil of radius $12 c m$ carrying a current of $2 A$ is

$18 G$

$19.7 G$

$15.7 G$

$17.7 G$

Here $N = 150$ ,
$R = 12 c m$
$= 12 \times 1 0^{- 2} m$ ,
$I = 2 A$
$∴ B = \frac{μ _{0} N I}{2 R}$
$= \frac{2 π \times 1 0 ^{- 7} \times 150 \times 2}{12 \times 1 0 ^{- 2}}$
$= 1.57 \times 1 0^{- 3} T$
$= 1.57 \times 1 0^{- 3} T$
$= 15.7 \times 1 0^{- 4} T$
$= 15.7 G$

Q. The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12cm carrying a current of 2A is

18G

19.7G

15.7G

17.7G