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  4. The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12 cm carrying a current of 2 A is

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Q. The magnitude of the magnetic field at the centre of the tightly wound $150$ turn coil of radius $12\, cm$ carrying a current of $2 \,A $ is

Moving Charges and Magnetism

Solution:

Here $N= 150$,
$R=12\,cm$
$=12\times10^{-2}\,m$,
$I=2\,A$
$\therefore B=\frac{\mu_{0} NI}{2R}$
$=\frac{2\pi\times10^{-7}\times150\times2}{12\times10^{-2}}$
$=1.57\times10^{-3}\,T $
$=1.57\times10^{-3}\,T $
$=15.7\times10^{-4}\,T $
$=15.7\,G$