The magnitude of electric field intensity E, such that an electron placed in it would experience an electrical force equal to its weight, is given by

Question

The magnitude of electric field intensity E, such that an electron placed in it would experience an electrical force equal to its weight, is given by (A) m g e (B) (mg/e) (C) (e/mg) (D) (e2/m2) g

Tardigrade Admin · Accepted Answer

Force on electron | F |= qE = eE = mg E =( mg / e )

Q. The magnitude of electric field intensity $E$ , such that an electron placed in it would experience an electrical force equal to its weight, is given by

$m g e$

$\frac{m g}{e}$

$\frac{e}{m g}$

$\frac{e ^{2}}{m ^{2}} g$

Force on electron
$∣ F ∣ = qE = e E = m g$
$E = \frac{m g}{e}$

Q. The magnitude of electric field intensity E, such that an electron placed in it would experience an electrical force equal to its weight, is given by

mge

emg​

mge​

m2e2​g