The magnitude of earth's magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length l, lying north-south, moves eastwards with a velocity ν. The emf induced across the rod is

Question

The magnitude of earth's magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length l, lying north-south, moves eastwards with a velocity ν. The emf induced across the rod is (A) zero (B) B0 l v (C) B0 l v sin δ (D) B0 l v cos δ

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fac96495797e267470f9c4c9dba37489-.png" /> The vertical component of the earth's magnetic field is BV=B0 sinδ. A conductor lying north-south moving horizontally is normal to BV. The emf induced is ε=B0 lv sin δ.

Q. The magnitude of earth's magnetic field at a place is $B_{0}$ and the angle of dip is $δ$ . A horizontal conductor of length $l$ , lying north-south, moves eastwards with a velocity $ν$ . The emf induced across the rod is

zero

$B_{0} l v$

$B_{0} l v sin δ$

$B_{0} l v cos δ$

The vertical component of the earth's magnetic field is $B_{V} = B_{0}$ sin\delta. A conductor lying north-south moving horizontally is normal to $B_{V}$ . The emf induced is $ε = B_{0} l v sin δ .$

Q. The magnitude of earth's magnetic field at a place is B0​ and the angle of dip is δ. A horizontal conductor of length l, lying north-south, moves eastwards with a velocity ν. The emf induced across the rod is

zero

B0​lv

B0​lvsinδ

B0​lvcosδ

The vertical component of the earth's magnetic field is BV​=B0​ sin\delta. A conductor lying north-south moving horizontally is normal to BV​. The emf induced is ε=B0​lvsinδ.

Q. The magnitude of earth's magnetic field at a place is $B_{0}$ and the angle of dip is $δ$ . A horizontal conductor of length $l$ , lying north-south, moves eastwards with a velocity $ν$ . The emf induced across the rod is

$B_{0} l v$

$B_{0} l v sin δ$

$B_{0} l v cos δ$

The vertical component of the earth's magnetic field is $B_{V} = B_{0}$ sin\delta. A conductor lying north-south moving horizontally is normal to $B_{V}$ . The emf induced is $ε = B_{0} l v sin δ .$