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  4. The magnitude of earth's magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length l, lying north-south, moves eastwards with a velocity ν. The emf induced across the rod is

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Q. The magnitude of earth's magnetic field at a place is $B_{0}$ and the angle of dip is $\delta$. A horizontal conductor of length $l$, lying north-south, moves eastwards with a velocity $\nu$. The emf induced across the rod is

Electromagnetic Induction

Solution:

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The vertical component of the earth's magnetic field is $B_{V}=B_{0}$ sin\delta. A conductor lying north-south moving horizontally is normal to $B_{V}$. The emf induced is $\varepsilon=B_{0} lv\sin \delta.$