The magnifying power of objective of a compound microscope is 5. If the magnifying power of microscope is 30, then magnifying power of eyepiece will be

Question

The magnifying power of objective of a compound microscope is 5. If the magnifying power of microscope is 30, then magnifying power of eyepiece will be (A) 0.17 (B) 6 (C) 3 (D) 25

Tardigrade Admin · Accepted Answer

Total magnification M =M0 × Me Given M = 30 and M0 = 5 ⇒ Me =(M/M0) = (30/5) = 6

Q. The magnifying power of objective of a compound microscope is 5. If the magnifying power of microscope is 30, then magnifying power of eyepiece will be

0.17

6

3

25

35

Total magnification
$M = M_{0} \times M_{e}$
Given $M = 30$ and $M_{0} = 5$
$\Rightarrow M_{e} = \frac{M}{M _{0}} = \frac{30}{5} = 6$

Q. The magnifying power of objective of a compound microscope is 5. If the magnifying power of microscope is 30, then magnifying power of eyepiece will be

0.17

6

3

25

35

Total magnification M=M0​×Me​ Given M=30 and M0​=5 ⇒Me​=M0​M​=530​=6

Total magnification
$M = M_{0} \times M_{e}$
Given $M = 30$ and $M_{0} = 5$
$\Rightarrow M_{e} = \frac{M}{M _{0}} = \frac{30}{5} = 6$