The magnifying power of a compound microscope increase with

Question

The magnifying power of a compound microscope increase with (A) the focal length of objective lens is increased and that of eye lens is decreased (B) the focal length of eye lens is increased and that of objective lens is decreased (C) focal lengths of both objects and eye-piece are increased (D) focal lengths of both objects and eye-piece are decreased

Tardigrade Admin · Accepted Answer

Magnifying power of compound microscope M=-(vt/uo)(1+(D/fe))=-(L/fo)(1+(D/fe))

Q. The magnifying power of a compound microscope increase with

the focal length of objective lens is increased and that of eye lens is decreased

the focal length of eye lens is increased and that of objective lens is decreased

focal lengths of both objects and eye-piece are increased

focal lengths of both objects and eye-piece are decreased

Magnifying power of compound microscope
$M = - \frac{v _{t}}{u _{o}} (1 + \frac{D}{f _{e}}) = - \frac{L}{f _{o}} (1 + \frac{D}{f _{e}})$

Q. The magnifying power of a compound microscope increase with

the focal length of objective lens is increased and that of eye lens is decreased

the focal length of eye lens is increased and that of objective lens is decreased

focal lengths of both objects and eye-piece are increased

focal lengths of both objects and eye-piece are decreased

Magnifying power of compound microscope M=−uo​vt​​(1+fe​D​)=−fo​L​(1+fe​D​)

Magnifying power of compound microscope
$M = - \frac{v _{t}}{u _{o}} (1 + \frac{D}{f _{e}}) = - \frac{L}{f _{o}} (1 + \frac{D}{f _{e}})$