Question

The magnetic moment (spin only) of ${\left[NiC{l}_4\right]}^{2-}$ is

• A. $1.41BM$
• B. $1.82BM$
• C. $5.46BM$
• D. $2.82BM$

Answer 1

Answer: (D)

Hybridisation of $Ni$ is $s{p}^3$

Unpaired $e^{-}$ in $3d^8$ is 2

So $\mu =\sqrt{n(n+2)}BM$

$=\sqrt{2\times 4}=\sqrt{8}=2.82BM$