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Q. The magnetic moment (spin only) of $\left[ NiCl _{4}\right]^{2-}$ is

AIEEEAIEEE 2011

Solution:

Hybridisation of $Ni$ is $s p^{3}$

Unpaired $e ^{-}$ in $3 d^{8}$ is 2

So $\mu = \sqrt{n(n + 2)} B M$

$=\sqrt{2 \times 4} = \sqrt{8} = 2.82 BM$