Question

The magnetic moment of the complex anion $[Cr(NO)(N{H}_3)(CN{)}_4{]}^{2-}$ is :

• A. 5.91 BM
• B. 3.87 BM
• C. 1.73 BM
• D. 2.82 BM

Answer 1

Answer: (D)

In $[Cr(NO)(N{H}_3)(CN{)}_4{]}^{2-}$,
$C{r}^{2+}(d^4)$ is given as :
i.e., 2 unpaired electrons
$\mu =\sqrt{2\left(2+2\right)}=\sqrt{8}=2.82$