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  4. The magnetic moment of the complex anion [Cr(NO)(NH3)(CN)4]2- is :

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Q. The magnetic moment of the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$ is :

JEE MainJEE Main 2013Coordination Compounds

Solution:

In $[Cr(NO)(NH_3)(CN)_4]^{2-}$,
$Cr^{2+}(d^4)$ is given as :
i.e., 2 unpaired electrons
$\mu=\sqrt{2\left(2+2\right)}=\sqrt{8}=2.82$

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