The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :

Question

The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by : (A)  vecμ L =( e L /2 m ) (B)  vecμ L =-(e L /2 m ) (C)  vecμ1=-(e vecL/m) (D)  vecμ1=(2 e vecL/m)

Tardigrade Admin · Accepted Answer

Ratio of magnetic moment and angular momentum ( vecμ/ L )=( q /2 m ) For - vecμ=-( e /2 m ) L

Q. The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :

$μ_{L} = \frac{e L}{2 m}$

$μ_{L} = - \frac{e L}{2 m}$

$μ_{1} = - \frac{e L}{m}$

$μ_{1} = \frac{2 e L}{m}$

Ratio of magnetic moment and angular momentum
$\frac{μ}{L} = \frac{q}{2 m}$
For $^{-}$
$μ = - \frac{e}{2 m} L$

Q. The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :

μ​L​=2meL​

μ​L​=−2meL​

μ​1​=−meL​

μ​1​=m2eL​

Ratio of magnetic moment and angular momentum Lμ​​=2mq​ For − μ​=−2me​L

$μ_{L} = \frac{e L}{2 m}$

$μ_{L} = - \frac{e L}{2 m}$

$μ_{1} = - \frac{e L}{m}$

$μ_{1} = \frac{2 e L}{m}$

Ratio of magnetic moment and angular momentum
$\frac{μ}{L} = \frac{q}{2 m}$
For $^{-}$
$μ = - \frac{e}{2 m} L$