The magnetic moment of a magnet is 0.1 amp × m 2. It is suspended in a magnetic field of intensity 3 × 10-4 weber/ m 2. The couple acting upon it when deflected by 30° from the magnetic field is

Question

The magnetic moment of a magnet is 0.1 amp × m 2. It is suspended in a magnetic field of intensity 3 × 10-4 weber/ m 2. The couple acting upon it when deflected by 30° from the magnetic field is (A) 1 × 10-5 N m (B) 1.5 × 10-5 Nm (C) 2 × 1025 Nm (D) 2.5 × 10-5 N m

Tardigrade Admin · Accepted Answer

τ= MB sin θ=0.1 × 3 × 10-4 sin 30° or τ=1.5 × 10-5 N - m

Q. The magnetic moment of a magnet is $0.1 am p \times m^{2}$ . It is suspended in a magnetic field of intensity $3 \times 1 0^{- 4}$ weber/ $m^{2}$ . The couple acting upon it when deflected by $3 0^{\circ}$ from the magnetic field is

$1 \times 1 0^{- 5} N m$

$1.5 \times 1 0^{- 5} N m$

$2 \times 1 0^{25} N m$

$2.5 \times 1 0^{- 5} N m$

$τ = MB sin θ = 0.1 \times 3 \times 1 0^{- 4} sin 3 0^{\circ}$
or $τ = 1.5 \times 1 0^{- 5} N - m$

Q. The magnetic moment of a magnet is 0.1amp×m2. It is suspended in a magnetic field of intensity 3×10−4 weber/ m2. The couple acting upon it when deflected by 30∘ from the magnetic field is

1×10−5Nm

1.5×10−5Nm

2×1025Nm

2.5×10−5Nm